Description
We use a composition of two predicates inside(-1,1).and(lt(-1)) to filter numbers that are greater than -1 and less -1. Obviously, no values satisfy this condition. Therefore, we expect Tinkergraph returns an empty set. However, a vertex is returned.
gremlin> :> g.V().where(__.in('knows').count().is(inside(-1,1).and(lt(-1))))
==>v[0]
The graph of this example is as following.
Vertex bob = g.addV("person").property("name", "Bob").next(); // v[0] Vertex alice = g.addV("person").property("name", "Alice").next(); // v[1] Edge edge1 = g.addE("knows").from(bob).to(alice).next();
Attachments
Issue Links
- is duplicated by
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TINKERPOP-2892 Incorrectly comparing a counted value with a predicate outside
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- Closed
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