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  1. Spark
  2. SPARK-26449

Missing Dataframe.transform API in Python API

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Details

    • Improvement
    • Status: Resolved
    • Minor
    • Resolution: Fixed
    • 2.4.0
    • 3.0.0
    • PySpark, SQL
    • None
    • Patch

    Description

      I would like to chain custom transformations as is suggested in this blog post

      This will allow to write something like the following:

       

       

       
      def with_greeting(df):
          return df.withColumn("greeting", lit("hi"))
      
      def with_something(df, something):
          return df.withColumn("something", lit(something))
      
      data = [("jose", 1), ("li", 2), ("liz", 3)]
      source_df = spark.createDataFrame(data, ["name", "age"])
      
      actual_df = (source_df
          .transform(with_greeting)
          .transform(lambda df: with_something(df, "crazy")))
      print(actual_df.show())
      +----+---+--------+---------+
      |name|age|greeting|something|
      +----+---+--------+---------+
      |jose|  1|      hi|    crazy|
      |  li|  2|      hi|    crazy|
      | liz|  3|      hi|    crazy|
      +----+---+--------+---------+
      
      

      The only thing needed to accomplish this is the following simple method for DataFrame:

      from pyspark.sql.dataframe import DataFrame 
      def transform(self, f): 
          return f(self) 
      DataFrame.transform = transform
      

      I volunteer to do the pull request if approved (at least the python part)

       

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              EC83 Erik Christiansen
              chanansh Hanan Shteingart
              Maciej Szymkiewicz Maciej Szymkiewicz
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