I'm using openejb to test a servlet and got a wrong PathInfo from org.apache.openejb.server.httpd.HttpRequestImpl class because method getPathInfo is returning a path containg the servlet path.
My servlet path is /servlet and the request /app/servlet/test is returning /servlet/test as both getServletPath and getPathInfo, but the correct path info would be /test only.
I verified that the getPathInfo implementation can strip the servletPath but the method initServletPath is not called, so servletPath is null.
Accoding to Servlet Spec 3.x, section 3.5 Request Path Elements, we have:
The request path that leads to a servlet servicing a request is composed of many
important sections. The following elements are obtained from the request URI path
and exposed via the request object:
- Context Path: The path prefix associated with the ServletContext that this
servlet is a part of. If this context is the “default” context rooted at the base of the
Web server’s URL name space, this path will be an empty string. Otherwise, if the
context is not rooted at the root of the server’s name space, the path starts with a
/ character but does not end with a / character.
- Servlet Path: The path section that directly corresponds to the mapping which
activated this request. This path starts with a ’/’ character except in the case
where the request is matched with the ‘/*’ or ““ pattern, in which case it is an
- PathInfo: The part of the request path that is not part of the Context Path or the
Servlet Path. It is either null if there is no extra path, or is a string with a leading
The following methods exist in the HttpServletRequest interface to access this
It is important to note that, except for URL encoding differences between the request
URI and the path parts, the following equation is always true:
requestURI = contextPath + servletPath + pathInfo