Details
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Bug
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Status: Closed
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Major
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Resolution: Not A Problem
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None
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None
Description
I tried to output an array column instead of multiple columns using the optional parameter output_type, but it throws an error:
--This is based on the example from the documentation page --This works ok SELECT madlib.pivot(source_table := 'pivset', out_table := 'pivout', index := 'id', pivot_cols := 'piv', pivot_values := 'val'); pivot ------- (1 row) --Adding the optional parameter, output_type, doesn't work: SELECT madlib.pivot(source_table := 'pivset', out_table := 'pivout', index := 'id', pivot_cols := 'piv', pivot_values := 'val', output_type := 'array'); ERROR: function madlib.pivot(source_table => unknown, out_table => unknown, index => unknown, pivot_cols => unknown, pivot_values => unknown, output_type => unknown) does not exist
Looking at the corresponding madlib.pivot() function, there's no parameter defined as default, so it seems that you can't have optional parameters as stated on the documentation?