[LANG-140] [lang] DurationFormatUtils.formatPeriod() returns the wrong result

• Type: Bug
• Status: Closed
• Priority: Major
• Resolution: Fixed
• Fix Version/s: 2.2

Environment

Operating System: Windows XP
Platform: PC

• Bugzilla Id: 38401
• Assignee: Henri Yandell
• Reporter: yu.peng
• Created: 26/Jan/06 22:41
• Updated: 06/Feb/07 23:47
• Resolved: 19/Jun/06 19:49

Description

/**

• lib: commons-lang-2.1.jar
• this class run result.
• Result:
• Date1->Date2=2006/01/26 18:47:34 000->2006/02/26 10:47:34 000===0000”N01
  ŒŽ-1“ú 16:00:00 000
• Date1->Date2=2006/01/26 18:47:34 000->2006/02/26 10:47:34 000===0000/01/-
  1 16:00:00 000
• want result:
• Date1->Date2=2006/01/26 18:47:34 000->2006/02/26 10:47:34 000===0000”N00ŒŽ
  30“ú 16:00:00
• Date1->Date2=2006/01/26 18:47:34 000->2006/02/26 10:47:34
  000===0000/00/30 16:00:00
• the results are wrong.

• */

import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;

import org.apache.commons.lang.time.DurationFormatUtils;

public class Test {

static SimpleDateFormat formatter = new SimpleDateFormat("yyyy/MM/dd
HH:mm:ss SSS");

public static void main(String[] args)

{ Date date1 = newDate(2006, 1, 26, 18, 47, 34); Date date2 = newDate(2006, 2, 26, 10, 47, 34); System.out.println("Date1->Date2=" + formatter.format(date1) + "->" + formatter.format(date2) + "===" + DurationFormatUtils.formatPeriod(date1.getTime(), date2.getTime (), "yyyy”NMMŒŽdd“ú HH:mm:ss SSS") ); System.out.println("Date1->Date2=" + formatter.format(date1) + "->" + formatter.format(date2) + "===" + DurationFormatUtils.formatPeriod(date1.getTime(), date2.getTime (), "yyyy/MM/dd HH:mm:ss SSS") ); }

public static Date newDate(int y, int m, int d, int h, int mi, int s)

{ Calendar calendar1 = Calendar.getInstance(); calendar1.clear(); calendar1.set(y, m - 1, d, h, mi, s); Date date1 = calendar1.getTime(); return date1; }

}