Details
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Sub-task
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Status: Resolved
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Blocker
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Resolution: Fixed
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None
Description
We currently set the default to 3 if idempotence is enabled. There was a brief discussion in the PR, but it would be good to explain this choice in more detail. Namely, what cases are we trying to cover with this number and have we considered the fact that with the default retry backoff of 100ms, 3 retries are used pretty quickly.
Is there a downside in using a larger retry count?
cc apurva
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