Details
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Bug
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Status: Closed
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Major
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Resolution: Fixed
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1.16.0
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None
Description
Pattern: begin("A", SkipToNext()).oneOrMore().allowCombinations().followedBy("C").notFollowedBy("B").within(Time.milliseconds(10L))
Sequence: <a1, 1L> <a2, 2L> <a3, 3L> <c1, 4L> will produce
[a1, a2, a3, c1]
[a1, a2, c1]
[a1, c1]
[a2, a3, c1]
[a2, c1]
[a3, c1]
Using SkipPastLastEvent() also produce the same result.
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Issue Links
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