[EXEC-68] Watchdog kills process immediately if timeout is too large

• Type: Bug
• Status: Resolved
• Priority: Minor
• Resolution: Fixed
• Affects Version/s: 1.1, 1.2
• Fix Version/s: 1.2

Environment

Should exist for all platforms, but specifically identified on Windows 7.

• Assignee: Unassigned
• Reporter: Joel McCance
• Created: 22/Oct/12 17:04
• Updated: 28/Dec/13 18:23
• Resolved: 22/Oct/12 19:22

Description

When using the ExecuteWatchdog with a very large timeout (e.g., Long.MAX_VALUE), the Watchdog immediately destroys the process instead of waiting for the duration of the timeout. For example, the following code snippet would continue immediately:

DefaultExecutor executor = new DefaultExecutor();
ExecuteWatchdog watchdog = new ExecuteWatchdog(Long.MAX_VALUE);
executor.setWatchdog(watchdog);

executor.execute(cmd); // Where `cmd` could be any valid command.

Issue Links

• relates to: EXEC-44 ExecuteWatchdog should accept infinite timeouts (argument -1)