Details
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Bug
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Status: Closed
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Major
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Resolution: Fixed
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1.29.0
Description
Double JOIN is created for NOT IN when IN-list that the values all non-nullable is converted to Values.
For example:
select * from "scott".emp where (empno, deptno) not in ((7369, 20), (7499, 30));
Before fix(Double Join):
EnumerableCalc(expr#0..14=[{inputs}], expr#15=[0:BIGINT], expr#16=[=($t8, $t15)], expr#17=[IS NULL($t14)], expr#18=[>=($t9, $t8)], expr#19=[IS NOT NULL($t11)], expr#20=[AND($t17, $t18, $t19)], expr#21=[OR($t16, $t20)], proj#0..7=[{exprs}], $condition=[$t21]) EnumerableMergeJoin(condition=[AND(=($10, $12), =($11, $13))], joinType=[left]) EnumerableSort(sort0=[$10], sort1=[$11], dir0=[ASC], dir1=[ASC]) EnumerableCalc(expr#0..9=[{inputs}], proj#0..9=[{exprs}], EMPNO0=[$t0], DEPTNO0=[/$t7]) EnumerableNestedLoopJoin(condition=[true], joinType=[inner]) EnumerableTableScan(table=[[scott, EMP]]) EnumerableAggregate(group=[{}], agg#0=[COUNT()], agg#1=[COUNT($1)]) EnumerableValues(tuples=[[{ 7369, 20 }, { 7499, 30 }]]) EnumerableSort(sort0=[$0], sort1=[$1], dir0=[ASC], dir1=[ASC]) EnumerableCalc(expr#0..1=[{inputs}], expr#2=[true], proj#0..2=[{exprs}]) EnumerableValues(tuples=[[{ 7369, 20 }, { 7499, 30 }]])
After Fix:
EnumerableCalc(expr#0..12=[{inputs}], expr#13=[IS NOT TRUE($t12)], expr#14=[IS NULL($t9)], expr#15=[OR($t13, $t14)], proj#0..7=[{exprs}], $condition=[$t15]) EnumerableMergeJoin(condition=[AND(=($8, $10), =($9, $11))], joinType=[left]) EnumerableSort(sort0=[$8], sort1=[$9], dir0=[ASC], dir1=[ASC]) EnumerableCalc(expr#0..7=[{inputs}], proj#0..7=[{exprs}], EMPNO0=[$t0], DEPTNO0=[$t7]) EnumerableTableScan(table=[[scott, EMP]]) EnumerableSort(sort0=[$0], sort1=[$1], dir0=[ASC], dir1=[ASC]) EnumerableCalc(expr#0..1=[{inputs}], expr#2=[true], proj#0..2=[{exprs}]) EnumerableValues(tuples=[[{ 7369, 20 }, { 7499, 30 }]])
Attachments
Issue Links
- relates to
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CALCITE-4889 Double join is created for NOT IN when IN-list is converted to Values
- In Progress
- links to