Details
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Improvement
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Status: Closed
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Major
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Resolution: Fixed
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None
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Description
When the query has one distinct aggregate and one or more non-distinct aggregates, the join instance need not produce the join-based plan. We can generate multi-phase aggregates. Another approach would be to use grouping sets. However, this transformation will be useful when systems don't support grouping sets and instead rely on the join-based plans (see the plan below)
select emp.empno, count(*), avg(distinct dept.deptno) from sales.emp emp inner join sales.dept dept on emp.deptno = dept.deptno group by emp.empno LogicalProject(EMPNO=[$0], EXPR$1=[$1], EXPR$2=[$3]) LogicalJoin(condition=[IS NOT DISTINCT FROM($0, $2)], joinType=[inner]) LogicalAggregate(group=[{0}], EXPR$1=[COUNT()]) LogicalProject(EMPNO=[$0], DEPTNO0=[$9]) LogicalJoin(condition=[=($7, $9)], joinType=[inner]) LogicalTableScan(table=[[CATALOG, SALES, EMP]]) LogicalTableScan(table=[[CATALOG, SALES, DEPT]]) LogicalAggregate(group=[{0}], EXPR$2=[AVG($1)]) LogicalAggregate(group=[{0, 1}]) LogicalProject(EMPNO=[$0], DEPTNO0=[$9]) LogicalJoin(condition=[=($7, $9)], joinType=[inner]) LogicalTableScan(table=[[CATALOG, SALES, EMP]]) LogicalTableScan(table=[[CATALOG, SALES, DEPT]])
The more efficient form should look like
select emp.empno, count(*), avg(distinct dept.deptno) from sales.emp emp inner join sales.dept dept on emp.deptno = dept.deptno group by emp.empno LogicalAggregate(group=[{0}], EXPR$1=[SUM($2)], EXPR$2=[AVG($1)]) LogicalAggregate(group=[{0, 1}], EXPR$1=[COUNT()]) LogicalProject(EMPNO=[$0], DEPTNO0=[$9]) LogicalJoin(condition=[=($7, $9)], joinType=[inner]) LogicalTableScan(table=[[CATALOG, SALES, EMP]]) LogicalTableScan(table=[[CATALOG, SALES, DEPT]])
Attachments
Issue Links
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CALCITE-1356 Release Calcite 1.9.0
- Closed