[XALANJ-2324] XPath function last() gives wrong result when select has a predicate

• Type: Bug
• Status: Closed
• Priority: Major
• Resolution: Duplicate
• Affects Version/s: 2.7
• Fix Version/s: 2.7.1
• Component/s: Xalan-interpretive, XPath-function
• Assignee: Unassigned
• Reporter: Brian Minchau
• Created: 06/Oct/06 15:51
• Updated: 12/Dec/07 03:44
• Resolved: 12/Oct/06 15:57

Description

Here is the testcase, the input XML is this:
<?xml version="1.0" encoding="UTF-8"?>
<project>
<author>
<firstname>Bugs</firstname>
<initial>B</initial>
<lastname>Gone</lastname>
</author>
</project>

The stylesheet is this:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8"/>

<xsl:template match="author">
<xsl:for-each select='(child::*)[not(self::initial)]'>
Child element <xsl:value-of select="position()"/>
of <xsl:value-of select="last()"/>
Element name: <xsl:value-of select="name()"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

The current, and incorrect output is this:
Child element 1
of 3
Element name: firstname
Child element 2
of 3
Element name: lastname

The selected elements are correct, but the last() function is returning 3 rather than 2.
If the for-each is changed to this:
<xsl:for-each select='(child::*)[not(self::junk)]'>
it iterates over the 3 children correctly (there is no child named 'junk' so the predicate does not reduce the sequence selected by (child::*), but in this case last() returns 4. In both cases one greater than it should.

With no predicate things work fine.

Issue Links

• duplicates: XALANJ-2286 count function applied to union as test of node identity is broken
• relates to: XALANJ-2204 Function Count on variable modifies number of nodes in variable.