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  1. Tajo (Retired)
  2. TAJO-934

Multiple DISTINCT returns null grouping key value.

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Details

    • Bug
    • Status: Resolved
    • Minor
    • Resolution: Fixed
    • None
    • 0.9.0
    • None
    • None

    Description

      default> select count * from table1;
      col1, col2, col3
      -------------------------
      a, b-1, null
      a, b-2, null
      a, b-2, null
      a, b-3, null
      a, b-3, null
      a, b-3, null
      
      default> select col1,
      count(distinct col2) as cnt1,
      count(distinct case when col3 is not null then col2 else null end) as cnt2
      from table1
      group by col1;
      
      col1,cnt1,cnt2
      -------------------------------
      a,  2,  1
      null,  1,  1
      

      This query should return the below result.

      col1,cnt1,cnt2
      -------------------------------
      a, 3, 1
      

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            hjkim Hyoungjun Kim
            hjkim Hyoungjun Kim
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            Dates

              Created:
              Updated:
              Resolved: