[SQOOP-452] Mysql free form queries fail if alias is not used.

• Type: Bug
• Status: Resolved
• Priority: Minor
• Resolution: Fixed
• Affects Version/s: 1.4.0-incubating
• Fix Version/s: 1.4.2
• Component/s: connectors/mysql
• Assignee: Cheolsoo Park
• Reporter: Prashant Gokhale
• Created: 02/Mar/12 20:36
• Updated: 25/Jul/12 19:50
• Resolved: 04/Apr/12 18:46

Description

Command I am running:
sqoop import --connect jdbc:mysql://<mysqlhost>/mysqltestdb --username xxx --password xxxx --query 'select testtable.id, testtable2.fname from testtable join testtable2 on (testtable.id = testtable2.id ) where testtable.id < 3 AND $CONDITIONS' --split-by testtable.id --target-dir joinresults

Sqoop fails with this error message

2/03/02 12:12:08 INFO db.DataDrivenDBInputFormat: BoundingValsQuery: SELECT MIN(testtable.id), MAX(testtable.id) FROM (select testtable.id as id, testtable2.fname as fname from testtable join testtable2 on (testtable.id = testtable2.id ) where testtable.id < 3 AND  (1 = 1) ) AS t1
12/03/02 12:12:08 INFO mapreduce.JobSubmitter: Cleaning up the staging area /user/prashant/.staging/job_1330641624236_0016
12/03/02 12:12:09 ERROR security.UserGroupInformation: PriviledgedActionException as:prashant (auth:SIMPLE) cause:java.io.IOException: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'testtable.id' in 'field list'
12/03/02 12:12:09 ERROR tool.ImportTool: Encountered IOException running import job: java.io.IOException: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'testtable.id' in 'field list'

The job runs successfully if I modify the query:

sqoop import --connect jdbc:mysql://<mysqlhost>/mysqltestdb --username xxxx --password xxxx --query 'select t1.id as id, t2.fname as fname from testtable as t1 join testtable2 as t2 on (t1.id = t2.id ) where t1.id < 3 AND $CONDITIONS' --split-by t1.id --target-dir joinresults

It would be nice to have it documented at least.