Description
spark-sql> select * from t10 where c0='abcd'; 20/12/22 15:43:38 ERROR SparkSQLDriver: Failed in [select * from t10 where c0='abcd'] scala.MatchError: CharType(10) (of class org.apache.spark.sql.types.CharType) at org.apache.spark.sql.catalyst.expressions.CastBase.cast(Cast.scala:815) at org.apache.spark.sql.catalyst.expressions.CastBase.cast$lzycompute(Cast.scala:842) at org.apache.spark.sql.catalyst.expressions.CastBase.cast(Cast.scala:842) at org.apache.spark.sql.catalyst.expressions.CastBase.nullSafeEval(Cast.scala:844) at org.apache.spark.sql.catalyst.expressions.UnaryExpression.eval(Expression.scala:476) at org.apache.spark.sql.catalyst.catalog.CatalogTablePartition.$anonfun$toRow$2(interface.scala:164) at scala.collection.TraversableLike.$anonfun$map$1(TraversableLike.scala:238) at scala.collection.Iterator.foreach(Iterator.scala:941) at scala.collection.Iterator.foreach$(Iterator.scala:941) at scala.collection.AbstractIterator.foreach(Iterator.scala:1429) at scala.collection.IterableLike.foreach(IterableLike.scala:74) at scala.collection.IterableLike.foreach$(IterableLike.scala:73) at org.apache.spark.sql.types.StructType.foreach(StructType.scala:102) at scala.collection.TraversableLike.map(TraversableLike.scala:238) at scala.collection.TraversableLike.map$(TraversableLike.scala:231) at org.apache.spark.sql.types.StructType.map(StructType.scala:102) at org.apache.spark.sql.catalyst.catalog.CatalogTablePartition.toRow(interface.scala:158) at org.apache.spark.sql.catalyst.catalog.ExternalCatalogUtils$.$anonfun$prunePartitionsByFilter$3(ExternalCatalogUtils.scala:157) at org.apache.spark.sql.catalyst.catalog.ExternalCatalogUtils$.$anonfun$prunePartitionsByFilter$3$adapted(ExternalCatalogUtils.scala:156)
c0 is a partition column, it fails in partition pruning rule