[QPID-4147] python-qpid client does not handle interrupts on its selector

• Type: Bug
• Status: Closed
• Priority: Major
• Resolution: Fixed
• Fix Version/s: 0.19
• Component/s: Python Client
• Assignee: Rafael H. Schloming
• Reporter: Siddhesh Poyarekar
• Created: 18/Jul/12 15:23
• Updated: 29/Jul/13 18:52
• Resolved: 30/Jul/12 23:06

Description

Description of problem:
python-qpid does not recover if its select() call within the Selector class has been interrupted. This is a problem when setuid() is called after a connection object has been created (hence a new thread has been created).

Version-Release number of selected component (if applicable):
python-qpid-0.14
python-qpid-0.12

How reproducible:
Always.

Steps to Reproduce:
1. Create a queue called justin
2. Run the following program:

#!/usr/bin/python
import os, sys, time
from qpid.messaging import Connection
from qpid.messaging import Message

addressdefault = 'localhost:5672'

if len(sys.argv) != 2:
host = addressdefault
else:
host = sys.argv[1]

def do_message():
conn = Connection(host)
conn.open()
sess = conn.session()
sender = sess.sender('justin')

message = Message(content='hello world!')
sender.send(message)

do_message()

try:
os.setuid(500)
except:
print "Exception has happened"
pass

do_message()

Actual results:

Traceback:

Exception in thread Thread-1:
Traceback (most recent call last):
File "/usr/lib64/python2.4/threading.py", line 442, in __bootstrap
self.run()
File "/usr/lib64/python2.4/threading.py", line 422, in run
self._target(*self.args, **self._kwargs)
File "/usr/lib/python2.4/site-packages/qpid/selector.py", line 119, in run
rd, wr, ex = select(self.reading, self.writing, (), timeout)
error: (4, 'Interrupted system call')

Expected results:

No traceback.