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  1. Qpid
  2. QPID-4102

Sender.send(timeout=N) should pass timeout=N to self.sync()

    Details

    • Type: Bug
    • Status: Closed
    • Priority: Minor
    • Resolution: Fixed
    • Affects Version/s: 0.16
    • Fix Version/s: 0.19
    • Component/s: Python Client
    • Labels:
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      Description

      Session.send(timeout=N) calls self.sync() with no timeout. In the case where self.capacity is UNLIMITED (the default) this can result in send() blocking indefinitely, even if called with a timeout. timeout=N should be passed through to the self.sync() call.

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            • Assignee:
              justi9 Justin Ross
              Reporter:
              mbonnet Mike Bonnet
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              • Created:
                Updated:
                Resolved: