[KARAF-3853] Use configured Java path to startup wrapper

• Type: Wish
• Status: Resolved
• Priority: Major
• Resolution: Fixed
• Affects Version/s: 3.0.3
• Fix Version/s: 4.1.0, 3.0.6, 4.0.5
• Assignee: Jean-Baptiste Onofré
• Reporter: Christian Lutz
• Created: 14/Jul/15 06:09
• Updated: 08/Feb/16 16:43
• Resolved: 08/Feb/16 16:43

Description

I stumbled across the following situation. A windows Server 2012 R2 installed a JDK7 with a public JRE (http://stackoverflow.com/questions/21412853/java-windows7-system32-folder-java-exe).

Now, I tried to install a karaf with a provided jdk 8. Starting this via the command line worked fine. After the first start I installed the service-wrapper, so far so good. But starting the server via the windows server brought me some trouble, because JRE 7 had been used to startup.

First I didn't understand why, because in the wrapper.conf the correct path to karaf/opt/jdk was configured. But then I found this "By default, the wrapper sets the JAVA_HOME in etc/karaf-wrapper.conf file. However, the bin/karaf-service script uses java. If required, you have to define the JAVA_HOME in this bin/karaf-service script." I found this sentence in section "Configuration Hint" version 2.3 and it helped me a lot.

So my wish is, either add this sentence to the current documentation, also. Or much better use the configured Java path within wrapper.conf to startup the service.