[GROOVY-10176] @NamedVariant with primitives can't find method

• Type: Bug
• Status: Closed
• Priority: Major
• Resolution: Fixed
• Affects Version/s: 2.5.14, 3.0.8
• Fix Version/s: 2.5.16, 3.0.10, 4.0.0
• Labels: named-parameters
• Assignee: Eric Milles
• Reporter: Leonard Brünings
• Created: 19/Jul/21 09:44
• Updated: 08/Mar/22 12:16
• Resolved: 16/Feb/22 17:03

Description

When using @NamedVariant on a method that uses primitives, it cannot invoke the underlying method.

 

import groovy.transform.NamedVariant

@NamedVariant
def foo(String a = 'a', int b = 1, long c = 2L) {
 "$a-$b-$c"
}

assert foo(b: 2) == "a-2-2"

 

You can also try it directly in the new Groovy Console.

groovy.lang.MissingMethodException: No signature of method: Script1.foo() is applicable for argument types: (null, Integer, null) values: [null, 2, null]
Possible solutions: foo(), foo(java.lang.String, int), foo(java.lang.String, int, long), foo(java.lang.String), foo(java.util.Map), run()
	at Script1.foo(Script1.groovy)
	at Script1$foo.callCurrent(Unknown Source)
	at Script1.run(Script1.groovy:8) 

Issue Links

• relates to: GROOVY-9158 @NamedParam arguments don't get their default value when only named parameters are used in the method call
• relates to: GROOVY-10261 @NamedVariant: Default parameters on ctor/method are ignored when passing some named parameters