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  1. CXF
  2. CXF-5720

FIQL: No replace '*' character in the middle expression by '%' character

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Details

    • Bug
    • Status: Closed
    • Major
    • Resolution: Fixed
    • 3.0.0-milestone1, 3.0.0-milestone2, 2.7.11
    • 3.0, 2.7.12
    • JAX-RS
    • Moderate

    Description

      No replace '*' character by '%' character in the SQL query, when this one is located in the middle expression.
      example:
      street==Str*t*
      Currently the SQL is:
      ... where street LIKE 'Str*t%'
      While the SQL should be:
      ... where street LIKE 'Str%t%'

      Attachments

        1. patch.txt
          2 kB
          Romain Castan

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          People

            sergey_beryozkin Sergey Beryozkin
            tolosa-rom Romain Castan
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              Updated:
              Resolved:

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