[CXF-4039] If the wsdlLocation is not a valid URL, you class.getResource(...)

• Type: Improvement
• Status: Closed
• Priority: Major
• Resolution: Fixed
• Fix Version/s: 2.4.6, 2.5.2
• Component/s: Tooling
• Estimated Complexity: Unknown
• Assignee: Daniel Kulp
• Reporter: Daniel Kulp
• Created: 17/Jan/12 21:08
• Updated: 07/Feb/12 21:50
• Resolved: 17/Jan/12 21:49

Description

If the wsdlLocation is not a valid URL, we can detect that easily at code generation time with a simple "new URL(wsdlLocation)" and generate more usable code via a class.getResource call instead.