[CXF-2704] CXF JAX-RS "Content-Disposition" is lost for second multipart

• Type: Bug
• Status: Closed
• Priority: Critical
• Resolution: Fixed
• Affects Version/s: 2.2.6
• Fix Version/s: 2.2.10, 2.3
• Component/s: JAX-RS
• Labels: Content-disposition

Environment

deploy Restful service enhanced based on the sample: "jaxrs basic" in tomcat,
client: python 2.6 + httplib2

• Estimated Complexity: Novice
• Assignee: Unassigned
• Reporter: George Gao
• Created: 10/Mar/10 19:14
• Updated: 11/Oct/10 14:45
• Resolved: 09/Jul/10 20:37

Description

I create a RestFul service for dealing with multiparts:

Part 1: application/xml(form data)  Bean in server side
Part2: application/octet-stream  upload file,

But the "Content-disposition" of the part2 is translated into: key="ontent-disposition", so the information about
Content-disposition can not be retrieve in server side.

I want to find out the filename in the part2, but exception happen for:

Server side code:
Attachment att = atts.get(1);
String filename = att.getContentDisposition().getParameter("filename");

Client side code:
-----------------------------------------------------------------------
import httplib2

http = httplib2.Http()
url='http://ib11b02.lsf.platform.com:9000/webservice/upload'

body = """
--bqJky99mlBWa-ZuqjC53mG6EzbmlxB
Content-Disposition: form-data; name='data'
Content-Type: application/xml; charset=US-ASCII
Content-Transfer-Encoding: 8bit

<?xml version='1.0' encoding='UTF-8' standalone='yes'?> <Customer> <name>Sharon Gao3</name> </Customer>
--bqJky99mlBWa-ZuqjC53mG6EzbmlxB
Content-Disposition: form-data; name='file1'; filename='genome.jpeg';
Content-Type: application/octet-stream
Content-Transfer-Encoding: UTF-8
Content-ID: <file1>

PGh0bWw+CiAgPGhlYWQ+CiAgPC9oZWFkPgogIDxib2R5PgogICAgPHA+VGhpcyBpcyB0aGUg
Ym9keSBvZiB0aGUgbWVzc2FnZS48L3A+CiAgPC9ib2R5Pgo8L2h0bWw+Cg==

-bqJky99mlBWa-ZuqjC53mG6EzbmlxB-
"""

headers =

{'Content-Type': 'multipart/mixed; boundary=bqJky99mlBWa-ZuqjC53mG6EzbmlxB', 'Content-Length': str(len(body))}

response, content = http.request(url, 'POST', body=body, headers=headers)