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  1. Commons Collections
  2. COLLECTIONS-427

performance problem in SetUniqueList.retainAll()

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Details

    • Bug
    • Status: Closed
    • Major
    • Resolution: Fixed
    • 3.2.1
    • 4.0-alpha1, 4.0, 4.1
    • None
    • None
    • java 1.6.0_24
      Ubuntu 11.10

    Description

      I am encountering a performance problem in SetUniqueList.retainAll().
      It appears in version 3.2.1 and also in revision 1365132. I attached
      a test that exposes this problem and a patch that fixes it. On my
      machine, for this test, the patch provides a 621X speedup.

      To run the test, just do:

      $ java Test

      The output for the un-patched version is:
      Time is 6215

      The output for the patched version is:
      Time is 10

      There are two problems here. First, "SetUniqueList.retainAll()"
      should have similar implementation with the current implementation of
      "ListOrderedSet.retainAll()", which is more optimized. Second, even
      "ListOrderedSet.retainAll()" has a performance problem, which was
      reported and explained in detail in COLLECTIONS-426.

      The attached patch has two parts. The first part (the first loop) is
      inspired from COLLECTIONS-426. The second part (everything after the
      first loop) is in fact the current implementation of
      "ListOrderedSet.retainAll()", with some minor changes to adapt it for
      the current code. Overall, the attached patch is very similar to the
      COLLECTIONS-426 patch.

      I will rehash some of the information from COLLECTIONS-426 (which
      describes "ListOrderedSet.retainAll()") for the current
      "SetUniqueList.retainAll()".

      The current code for "SetUniqueList.retainAll()" is:

      public boolean retainAll(Collection<?> coll) {
          boolean result = super.retainAll(coll);
          set.retainAll(coll);
          return result;
      }
      

      where both "super.retainAll(coll)" and "set.retainAll(coll)" can have
      quadratic complexity, e.g., if "coll" is a List. Both these calls to
      "retainAll" are in fact calls to
      "java.util.AbstractCollection.retainAll()", which has the code:

      public boolean retainAll(Collection<?> c) {
          boolean modified = false;
          Iterator<E> e = iterator();
          while (e.hasNext()) {
              if (!c.contains(e.next())) {
                  e.remove();
                  modified = true;
              }
          }
          return modified;
      }
      

      which iterates over "this" and calls "contains()" on "c". Mapping
      this code back to "SetUniqueList.retainAll()" means that the code
      iterates over "this" and "set" and calls "contains()" on "coll". If
      "coll" has slow "contains()" (e.g., if "coll" is a list), then
      "SetUniqueList.retainAll()" has quadratic complexity.

      The patch iterates over "coll" and calls "contains()" on "set", which
      we know is fast, because "set" is a Set. For a more detailed
      discussion of the patch and the problem, see the current
      implementation of "ListOrderedSet.retainAll()", the discussion for
      COLLECTIONS-426, and the patch for COLLECTIONS-426.

      Is this a bug, or am I misunderstanding the intended behavior? If so,
      can you please confirm if the patch is correct?

      Attachments

        1. patch.diff
          1 kB
          Mert Guldur
        2. Test.java
          0.7 kB
          Mert Guldur

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            Unassigned Unassigned
            mertguldur Mert Guldur
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              Updated:
              Resolved:

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