Details
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Bug
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Status: Resolved
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Major
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Resolution: Fixed
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2.6.0, 2.7.0, 2.8.0
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None
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Novice
Description
When a REST service returns an HTTP error code (e.g. 404), the URI property of the exception is incorrect.
The URI is the URI of the origin endpoint of the route.
It should be instead the URI of the endpoint that threw the exception.
For instance, in the following route :
<route id="restproxy"> <from uri="restlet:http://localhost:9080/oe/ws/offre/{id}"/> <doTry> <to uri="restlet:http://bla.dot.com:8080/oe/ws/offre/{id}"/> <doCatch> <exception>org.apache.camel.CamelException</exception> <log message="URI=${exception.uri}"/> </doCatch> </doTry> </route>
The logged URI is "restlet:http://localhost:9080/oe/ws/offre/
{id}" but should be instead the real URI used, e.g. "restlet:http://bla.dot.com:8080/oe/ws/offre/1".
This bug might be fixed by the following code change in class org.apache.camel.component.restlet.RestletProducer, method populateRestletProducerException() :
- String uri = exchange.getFromEndpoint().getEndpointUri();
+ String uri = response.getRequest().getResourceRef()