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| Resolution Date: |
07/Mar/06 09:39 AM
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In the mod_python.publisher code, the code for performing basic authentication
has in a few spots code of the form:
if "__auth__" in func_code.co_names:
i = list(func_code.co_names).index("__auth__")
__auth__ = func_code.co_consts[i+1]
if hasattr(__auth__, "co_name"):
__auth__ = new.function(__auth__, globals())
found_auth = 1
What this does is that if the target of the request is a function and that function
contains a nested function, which in this case is called "__auth__", then that
nested function is turned into a callable object and is subsequently called to
determine if the user is able to perform the request.
In making the nested function callable, it uses "globals()". By using this though
it is using the globals from the mod_python.publisher module and not the
module which the nested function is contained within. This means that the
following code will actually fail.
import xxx
def function(req):
def __auth__(req,username,password):
return xxx.auth(req,username,password)
This is because the module "xxx" imported at global scope within the module isn't
available to the nested function when it is called as it is seeing the globals of
mod_python.publisher instead. To get around the problem, the import has to be
local to the nested function.
def function(req):
def __auth__(req,username,password):
import xxx
return xxx.auth(req,username,password)
Since in this case the auth function being called is a nested function, we know that
we can actually grab the globals for the correct module by getting "func_globals"
from the enclosing function.
if "__auth__" in func_code.co_names:
i = list(func_code.co_names).index("__auth__")
__auth__ = func_code.co_consts[i+1]
if hasattr(__auth__, "co_name"):
__auth__ = new.function(__auth__, object.func_globals)
found_auth = 1
Ie., instead of "globals()", use "object.func_globals" where "object is the enclosing
function object.
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Description
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In the mod_python.publisher code, the code for performing basic authentication
has in a few spots code of the form:
if "__auth__" in func_code.co_names:
i = list(func_code.co_names).index("__auth__")
__auth__ = func_code.co_consts[i+1]
if hasattr(__auth__, "co_name"):
__auth__ = new.function(__auth__, globals())
found_auth = 1
What this does is that if the target of the request is a function and that function
contains a nested function, which in this case is called "__auth__", then that
nested function is turned into a callable object and is subsequently called to
determine if the user is able to perform the request.
In making the nested function callable, it uses "globals()". By using this though
it is using the globals from the mod_python.publisher module and not the
module which the nested function is contained within. This means that the
following code will actually fail.
import xxx
def function(req):
def __auth__(req,username,password):
return xxx.auth(req,username,password)
This is because the module "xxx" imported at global scope within the module isn't
available to the nested function when it is called as it is seeing the globals of
mod_python.publisher instead. To get around the problem, the import has to be
local to the nested function.
def function(req):
def __auth__(req,username,password):
import xxx
return xxx.auth(req,username,password)
Since in this case the auth function being called is a nested function, we know that
we can actually grab the globals for the correct module by getting "func_globals"
from the enclosing function.
if "__auth__" in func_code.co_names:
i = list(func_code.co_names).index("__auth__")
__auth__ = func_code.co_consts[i+1]
if hasattr(__auth__, "co_name"):
__auth__ = new.function(__auth__, object.func_globals)
found_auth = 1
Ie., instead of "globals()", use "object.func_globals" where "object is the enclosing
function object. |
Show » |
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Specifically, the code is probably only gauranteed to work if the nested
auth functions are the first nested functions in the method. If they aren't
then any nested functions appearing before them must not have default
parameters.
Take for example the following code:
def func1():
def func2(a,b="b"):
pass
def __auth__(req,user,password):
pass
func_code = func1.func_code
print func_code.co_names
print func_code.co_consts
print list(func_code.co_names).index("__auth__")
print func_code.co_consts[list(func_code.co_names).index("__auth__")+1]
When run this produces:
('func2', '__auth__')
(None, 'b', <code object func2 at 0x61a60, file "bug.py", line 2>, <code object __auth__ at 0x61aa0, file "bug.py", line 4>)
1
<code object func2 at 0x61a60, file "bug.py", line 2>
Where the code is supposed to select __auth__(), it is errornously selecting
func2() instead. This is because the constants that represent the default
parameters of the first nested functions, are throwing out the calculation
to work out which is the code object for __auth__().
Even if func2() didn't exist, the selection process would also be thrown out
if __auth__() itself had any default parameters.
So far from what I can work out, there doesn't seem to be a way of knowing
when extra constants are inserted which correspond to default parameters
of nested functions.
Thus, to be safe, one must ensure auth functions are the first things to be
defined in the function and that the auth functions themselves should not
have any default parameters.